If the horizontal distance of the boat from the bridge is 25m and the height of the bridge is 25 m then find the angle of depression of the boat from the bridge brain.in
Answers
Answered by
2
45 degree is the angle of depression of the boat from the bridge because
10 theta equals perpendicular upon base
and perpendicular is 25 and base is also 25 hence tan theta = 25 upon 25
tan theta equals 1
hence theta become 45°
10 theta equals perpendicular upon base
and perpendicular is 25 and base is also 25 hence tan theta = 25 upon 25
tan theta equals 1
hence theta become 45°
Similar questions