If the hypotenuse of a right triangle is 20 CM. Then what is the maximum area of the triangle
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Answer:
Area= 1/2 b*h but 20^2=b^2+h^2 or
h=sqrt (400-b^2)
area= 1/2 * sqrt( )*b= 1/2 b*sqrt ( )
take the derivative, set darea/db =0, ans solve for b.
maximum area when the rectangle is a square, so that makes each side 20/√2
and the maximum area is thus 200 cm^2
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Step-by-step explanation:
area 1/2b h 20²2 =b²2+ h²2 or
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