If the hypotenuse of an isosceles right triangle is 4 root 2cm. find the perimter of the triangle
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Let the other two sides be x cm.
By Pythagoras theorem,
(4root2)^2 = x^2 + x^2.
32 = 2 × x^2
x^2 = 32 ÷ 2
x^2 = 16.
x = 4
So, Other two sides are 4 cm.
Perimeter = 4 + 4 + 4root 2
Perimeter = 8 + 4root 2
Perimeter = 4( 2 + root2) cm
Hope it helps !! ;-)
By Pythagoras theorem,
(4root2)^2 = x^2 + x^2.
32 = 2 × x^2
x^2 = 32 ÷ 2
x^2 = 16.
x = 4
So, Other two sides are 4 cm.
Perimeter = 4 + 4 + 4root 2
Perimeter = 8 + 4root 2
Perimeter = 4( 2 + root2) cm
Hope it helps !! ;-)
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