if the hypotenuse of an isosceles right triangle is 7 root 2 centimetre find the area of the circle inscribed in it
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Answer:
13.21cm²
Step-by-step explanation:
AC=7√2 therefore AB and BC= 7 [pythagoras}
radius of a circle inscribed in a right triangle is
(perpendicular+base-hypotenuse)x 1/2
r= [7+7-7√2]x1/2
r= 7(2-√2)x1/2
ar of inscribed circle= 22/7x7²x(2-√2)²= 77/2x(2-√2)²= 13.21cm²
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