If the hypotenuse of an isosceles triangle is 8root2. What will be its area??
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God knows best........
In the isosceles triangle opposite sides
are equal.
let the equal sides is a
x^2 + x^2 = (Hypotenuse)^2
2x^2 = (8.2^1/2)^2
2x^2 = (8)^2.(2^1/2)^2
2x^2 = 128
x^2 = 128/2
x^2 = 64
x = 64^1/2
x = 8,-8.
Therefore x = 8 (or) -8.
I hope it is helpful to you........
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