If the ideal ammeter reads 4 A, the reading of ideal voltmeter will be:
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15V
12V
10V
3V
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Answer:
Current in 5ohm resistance will be
= (15/5+3+12)x4
=(15/20) x4
=3 A
Now current in 3 and 12 ohm branch will be
4-3 A
= 1A
Voltage drop in 12ohm resistance
V=ir
V =1 x 12
= 12 volt
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