If the image distance is 30cm from the mirror and magnification
is 1.5, the distance of the object is :
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Answer:
Given,
Focal length, f=−30 cm if u=−x
real ⇒ same side ⇒v=−ve
Magnification, m=
u
v
⇒v=m×u=3×(−x)=−3x
From mirror formula,
f
1
=
v
1
+
u
1
We get
−30
1
=
−3x
1
+
−x
1
⇒
30
1
=
3x
1+3
⇒
4
3x
=3⇒x=40 cm
So object should be placed at 40 cm to the mirror.
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