Question

If the image of the point (3, 8) in the line px + 3y – 7 = 0 is the point(–1, –4), then find the value of p.

Answer 1

px + 3y – 7 = 0
-1p - 12 - 7= 0
-1p -19 = 0
-1p = 19
p = -19

Answer 2

The value of p is 1.

Given:

A line of equation px+3y-7 = 0 and a point (3,8) with its image is (-1,-4)

To Find:

Value of p

Solution:

The point is (3,8) and its image is (-1,-4)

The mid -point of both the points lies on the line.

And it satisfy the equation of line.

So, mid point = ($\frac{3-1}{2},\frac{8-4}{2}$)

Mid point = (1,2)

this point lies on the line and it satisfy the equation of line.

p+3*2-7 =0

p = 1

Hence, the value of p is 1.

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