Question

if the indicator of point A is -5 & the indicator of point B is 3 then d (A, B) =?​

Answer 1

Answer:

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Step-by-step explanation:

As we know that, Sum of all four angles of quadrilateral is 360o . ∠ ∠A + ∠ ∠B + ∠ ∠C + ∠ ∠D = 360° ∠ ∠A + ∠ ∠B + 100° + 60° = 360° ∠ ∠A + ∠ ∠B = 360° - 160° = 200° Now, according to question bisector of ∠ ∠A and ∠ ∠B meet in a point P and forms the triangle PAB. So, 1/2 ∠ ∠A + 1/2 ∠ ∠B = 200°/2 = 100° As we know that, sum of all angles of triangle is 180°. 1/2 ∠ ∠A + 1/2 ∠ ∠B + ∠ ∠APB = 180° 100° + ∠ ∠APB = 180° = 80° So, ∠ ∠APB = 80°Read more on Sarthaks.com - https://www.sarthaks.com/1131800/adjacent-figure-bisectors-ofa-andbmeet-point-ifc-100-andd-60-measure-ofapb?show=1131804#a1131804