If the induced emf in the stator of an 8 pole induction motor has a frequency of 50 Hz and that in the rotor is 1.5 Hz, at what speed is the motor running and what is the slip?
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The synchronous speed of the rotor in RPM N = 120f/P where f is the frequency of the stator current and P is the number of poles. The operating speed No = N - Ns where Ns is the slip speed. The frequency of the rotor current fr = Ns x P/120, so fr = 0 if the slip is zero.
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Speed of the motor running and slip is 0.03
Explanation:
f = 50 Hz and fr = 1.5 Hz,
Ns = 120f/p = 120 x 50/8 = 750 rpm
We have fr = sf
Hence s= fr/f = 1.5/50 = 0.03
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