Question

if the initial abd final velocity of moving body is 30cm and 3.70 meter per second respectively then the distan cover in 5 second will be
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Answer 1

Answer:

Explanation:

Correct Question,

If the initial aNd  final velocity of the moving body is 30 cm/s and 3.70 m/s respectively then the distance cover in 5 seconds will be .

Solution,

Here, We have

Initial velocity, u = 30 cm/s = 0.3 m/s

Final velocity, v = 3.70 m/s

Time taken, t = 5 seconds

To Find,

Distance traveled, s = ?

At 1st we have to find the acceleration,

According to the 1st equation of motion,

We know that,

v = u + at

So, putting all the values, we get

v = u + at

⇒ 3.70 = 0.3 + a × 5

⇒ 3.70 - 0.3 = 5a

⇒ 3.4 = 5a

⇒ 3.4/5 = a

⇒ a = 0.68 m/s²

Here, the acceleration is 0.68 m/s².

Now, we will find the distance traveled,

According to the 3rd equation of motion,

We know that,

v² - u² = 2as

So, putting all the values, again we get

v² - u² = 2as

⇒ (3.70)² - (0.3)² = 2 × 0.68 × s

⇒ 13.69 - 0.09 = 1.36s

⇒ 13.6 = 1.36s

⇒ 13.6/1.36 = s

⇒ s = 10 m.

Hence, the distance covered by the body is 10 m.

Answer 2

Answer:

u = 30 cm / s

v = 370 cm / s

t = 5 s

d = ?

By the first equation of motion :-

    v = u + at

  a = 370 - 30 / 5

     = 340 / 5

 a = 68 m / s²

By the second equation of motion :-

     distance = ut + 1/2 * at²

                      = 30 * 5 + 1/2 * 68 * 25

       = 150 + 850

        = 1000 cm or 10 m

Explanation:

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