if the initial and final velocities of a moving body are 30 cm/sec and 3.70 meter/sec respectively then the distance covered in 5 seconds will be ?
Answers
Answer:
The answer is 14.43m/s
Explanation:
The initial velocity is 30cm/sec = 0.3m/s
The final velocity is 3.7m/s
Time = 5s
Therefore, the acceleration is v-u/t
= 3.7 - 0.3/5 = 0.68
Therefore the distance covered = s=ut+1/2at^2
s = 0.3*5 + 1/2 *0.68*25
s = 14.34 metres.
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Answer:
Explanation:
Solution,
Here, We have
Initial velocity, u = 30 cm/s = 0.3 m/s
Final velocity, v = 3.70 m/s
Time taken, t = 5 seconds
To Find,
Distance traveled, s = ?
At 1st we have to find the acceleration,
According to the 1st equation of motion,
We know that,
v = u + at
So, putting all the values, we get
v = u + at
⇒ 3.70 = 0.3 + a × 5
⇒ 3.70 - 0.3 = 5a
⇒ 3.4 = 5a
⇒ 3.4/5 = a
⇒ a = 0.68 m/s²
Here, the acceleration is 0.68 m/s².
Now, we will find the distance traveled,
According to the 3rd equation of motion,
We know that,
v² - u² = 2as
So, putting all the values, again we get
v² - u² = 2as
⇒ (3.70)² - (0.3)² = 2 × 0.68 × s
⇒ 13.69 - 0.09 = 1.36s
⇒ 13.6 = 1.36s
⇒ 13.6/1.36 = s
⇒ s = 10 m.
Hence, the distance covered by the body is 10 m.