if the initial and final velocities of a moving body are 30 cm/sec and 3.70 m/sec, respectively, then the distance covered in 5 seconds will be: (B) 2 m (D) 10 m (A) 1 m (C) 5 m
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The initial velocity is 30cm/sec = 0.3m/s =u
The final velocity is 3.7m/s = v
Time = 5s = t
Therefore, the acceleration is (a)
=(v-u)/t
= 3.7 - 0.3/5 = 0.68 m/s^2
Therefore the distance covered
s=ut+1/2at^2
s = 0.3*5 + 1/2 *0.68*2
s = 14.34 metres.
Therefore, the body moves 14.34 metres in these conditions.
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