Question

If the initial point of vector

-2i^-3j^is (− 1, 5, 8) then the terminal point is

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Answer 1

Answer:

The vector whose initial and terminals points are coincide has the length 0. Hence we call it to be a zero vector and the zero vector no has the particular direction, so that it can be assigned in any direction.

Answer 2

The terminal point of the vector $(-2\hat{i}-3\hat{j})$ is $(-3,2,8)$, where the initial point is $(-1,5,8)$.

Step-by-step explanation:

$\boxed{\bold{NOTE:}}$

If any line segment $PQ$ represents any vector $\overrightarrow{v}$, then

$\quad \overrightarrow{v}=\overrightarrow{PQ}$

So, $\overrightarrow{PQ}$= position vector of Q - position vector of P

where P is initial point and Q terminal.

Solution:

Let, $(x,y,z)$ be the terminal point. Then,

$\quad (x,y,z)-(-1,5,8)=(-2,-3,0)$

$\Rightarrow (x+1,y-5,z-8)=(-2,-3,0)$

This gives:

• $x+1=-2\Rightarrow x=-3$
• $y-5=-3\Rightarrow y=2$
• $z-8=0\Rightarrow z=8$

So, the terminal point is $(-3,2,8)$.