if the initial speed of a particle is u and its acceleration is given as a is equals to At3 where A is constant and t is time then its speed we will be given as
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Given:
f=at
Where a is constant and time is t
f= dV/dt=at
Integrate on both sides.
Limits of velocity:
Initial velocity =u
Final velocity=V
Time initial=0
Final time=t
On integrating:
dV/dt=at
We get
V-u= 1/2 at^2
V=u+1/2at^2
Now on sq
V=u+at^4/4
HOPE IT HELPS U^_^
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if the initial speed of a particle is u and its acceleration is given as a is equals to At3 where A is constant and t is time then its speed we will be given as?
=> u + At^4 / 4
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