Question

If the initial velocity of a car is 30km/hr accelerates at 41km/hr.What will be the distance travelled if the time taken is 4hrs​

Answer 1

Answer:

The Equation of motion for a body in acceleration states is given by-

S=ut +1/2 at^2

s = distance traveled in time 't' (in m)

u = initial velocity (in m/s)

a = acceleration of the body (in m/sec^2)

t = time (in sec)

Explanation:

Initial velocity (u) = 30 km/hr

Converting this in m/sec, we get:

u=30×1000/3600

u=25/3 m/s

convert accelaration in sec ,We get-

a = 41×10/46

=11.39 m/s^2

Now, the distance traveled by the car for t = 14,400 sec can be obtained using the Equation of motion as:

S=ut +1/2 at^2

=25/3×14,400+1/2 (13.39)(14,400^2)

s = 33.33 + 385632

s = 385665/60

=6427.75