Question

If the initial velocity of an oblique projectile is 20 m/s and it makes an angle 60° with the horizontal, what are the components of velocity in
the horizontal and vertical direction?​

Answer 1

Answer:

Horizontal velocity = 10$\sqrt{3\\}$ m/s and vertical velocity = 10 m/s

Explanation:

velocity along horizontal = v sinθ = 20 sin(60°) = 20√3/2 = 10√3 m/s

velocity along vertical = v cosθ = 20 sin(60°) = 20/2 = 10 m/s.