If the intensity of the incident radiation on a photosensitive surface is doubled, how does the kinetic energy of the emitted electrons get affected ?
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Intensity of incident radiation means energy E incidents per second per unit area incident on photosensitive surface and
number of photons emitted =E/h(nue )
here h(nue) is energy of each photon and(nue) is frequency of each photon
when intensity is doubled that means energy is doubled hence number of photons emitted will be doubled.
This doubles total kinetic energy but kinetic energy of each photon remains the same
because it depends on frequency of incidence light and not on intensity.
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