Math, asked by dikshanishad70, 1 month ago


If the interest is₹76.50, time is 9 months and compound rate of interest is 6% p.a. compounded
quarterly, find the principal. ​

Answers

Answered by ItzCutePrince1946
5

Given:

The interest is ₹76.50, time is 9 months and compound rate of interest is 6% p.a. quarterly

To Find:

The principal amount

Solution

➝ Here as we have given the compound interest the rate of interest and the time let us find the principal using suitable formulae

{\underline{\mathbb{ As \; we \; know \; that \dag}}}

\;\;\;\;\;\;\;\;\;\dag \;\; \bigg [\bf Compound \; Interest = P\bigg( 1 + \frac{r}{400} \bigg)^{4n} - 1 \bigg]

→here,

C.I = 76.50

Rate = 9%

time =  9 months

→Substituting we get,

\implies \sf 76.50 = P \bigg[\bigg( 1 + \dfrac{9}{400} \bigg) ^{3}  - 1 \bigg]

\implies \sf 76.50 = P \bigg[\bigg( \dfrac{409}{400} \bigg)^{3}  - 1 \bigg]

\implies \sf 76.50 = P \bigg[\bigg( \dfrac{409}{400} \bigg)^{3}  - 1 \bigg]

\implies \sf 76.50 = P \bigg[\bigg( \dfrac{409}{400} \bigg)^{3}  - 1 \bigg]

\implies \sf 76.50 = P \times 1.06 - 1

\implies \sf  P =  1.06 - 1 \div 76.5

\implies \sf  P =  1.06 - 0.01

\implies \sf {\boxed{\pmb{\mathtt{ P= 1.05}}}}

  • Hence the principal amount is 1.05.

\huge\fbox{\pink{\underline{♥Thank \: You♥}}}

Answered by Anonymous
3

Given:

  • The interest is ₹76.50, time is 9 months and compound rate of interest is 6% p.a. quarterly

To Find:

  • the principal amount

Solution;

➝ Here as we have given the compound interest the rate of interest and the time let us find the principal using suitable formulae

{\underline{\frak{ As \; we \; know \; that \dag}}}

\;\;\;\;\;\;\;\;\;\dag \;\; \bigg [\bf Compound \; Interest = P\bigg( 1 + \frac{r}{400} \bigg)^{4n} - 1 \bigg]

here,

  • C.I = 76.50
  • Rate = 6%
  • time =  9 months

Substituting we get,

\implies \sf p+ 76.5 = P \bigg[\bigg( 1 + \dfrac{6}{400} \bigg) ^{3}    \bigg]

\implies \sf 76.50 = P \bigg[\bigg( \dfrac{406}{400} \bigg)^{3}  - p \bigg]

\implies \sf 76.50 = P \times 1.0458  - p

\implies \sf 76.50 = P ( 1.0458 - 1 )

\implies \sf 76.50 = P \times 0.0458

\implies \sf  P =  76.5 \div 0.0458

\implies \sf {\boxed{\pmb{\frak{ P= 1670.30}}}}

  • henceforth thee principal amount is 1.03

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