Math, asked by harshil2072, 11 months ago

if the interest is compounded every six months find compound interest 30000 at10% for 1year​

Answers

Answered by shanthini5343
0

Answer:

p =30000

n = 1 yrs

interest is compounded half yearly(6 months)

n = 2n = 2 x 1 =2 yrs

r = 10 %

again ,interest is compounded half yearly(6 months), so

r = r/2 = 10/2 =5%

A = P (1+(r/100))^n

A = 30000(1+(5/100))²

=30000 x (105/100) x(105/100)

= 3 x 105 x 105

A=33075

C.I = A -P

= 33075 -30000

= 3075

Step-by-step explanation:

Answered by hemangipandya456
0

Answer:

6,450

Step-by-step explanation:

P = 30,000  r= 20 %  n=1 year

∴ Amount after 1 year = P ( 1 + R/4 )^ 4n

= 30,000( 1+ 20/100*4) ^ 4*1

= 30,000(1+0.05 ) ^4

= 30,000(1.05) ^ 4

= 30,000(1.215)

= 36,450

∴ Compound interest = 36,450-30,000

                                     = 6,450

Regards.

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