if the interest is compounded every six months find compound interest 30000 at10% for 1year
Answers
Answered by
0
Answer:
p =30000
n = 1 yrs
interest is compounded half yearly(6 months)
n = 2n = 2 x 1 =2 yrs
r = 10 %
again ,interest is compounded half yearly(6 months), so
r = r/2 = 10/2 =5%
A = P (1+(r/100))^n
A = 30000(1+(5/100))²
=30000 x (105/100) x(105/100)
= 3 x 105 x 105
A=33075
C.I = A -P
= 33075 -30000
= 3075
Step-by-step explanation:
Answered by
0
Answer:
6,450
Step-by-step explanation:
P = 30,000 r= 20 % n=1 year
∴ Amount after 1 year = P ( 1 + R/4 )^ 4n
= 30,000( 1+ 20/100*4) ^ 4*1
= 30,000(1+0.05 ) ^4
= 30,000(1.05) ^ 4
= 30,000(1.215)
= 36,450
∴ Compound interest = 36,450-30,000
= 6,450
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