Math, asked by sejalsonar1991, 4 days ago

If the interest on 3000 rupees is 600 rupees at a certain rate for a certain number of years, what would the interest be on 1500 rupees under the same conditions ?​

Answers

Answered by BidishaGuha27
0

Answer:

Rs. 300

Step-by-step explanation:

Int. On 3000 rs. = 600

Int. On 1500 rs. = (600×1500)/3000

= 300

Answered by ELBERTEINSTIEN
0

Step-by-step explanation:

Complete step by step answer:

Let the interest on 3000 rupees is 600 rupees at a certain rate for a certain number of years.

Let the years be n and the interest rate be r.

We know that if the principal amount be p and the amount of interest is a, then the formula of finding the interest is defined by a=pnr100.

For our given problem it’s given the interest on 3000 rupees is 600 rupees at a rate of r for n years.

We put the values a=600,p=3000 in the equation a=pnr100.

We get 600=3000×nr100. Solving the equation, we get the value of nr.

600=3000nr100⇒nr=100×6003000=20

Now we have to find the interest on 1500 rupees at a rate of r for n years. The rate of interest and the time frame hasn’t been changed.

Let the interest be y. Then y=pnr100. Here p will be 1500.

So, y=1500×20100=300.

Therefore, the interest on 1500 rupees under the same conditions will be 300 Rs.

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