Question

If the interest on rs 3,000 at a certain rate for a certain number of years is rs 600, what would be the interest on rs 1,500 under the same condition?​

Answer 1

Answer:

₹300

Step-by-step explanation:

p=3000

S.I.=600

R=S.I.×100/p×t

=600×100/3000×t

=20/t

p=1500

r=20/t

S.I.=p×r×t

=1500×20×t/t×100

=₹300

time will be cutted as r =20/t

Answer 2

Answer:

S.I.= Rs. 300

Step-by-step explanation:

S.I.= Rs 600

Principal= Rs. 3000

Let the Rate be 'r%' p.a.

Let the Time be 't' yrs.

Alq,

$600 = (3000 \times r \times t) \div 100 \\ = > 600 = 30rt \\ = > rt = 600 \div 30 \\ = > rt = 20$

Now,

Principal= Rs. 1500

We know,

rt=20

Therefore,

S.I.= Rs. 300

$(prt) \div 100 \\ = (1500 \times rt) \div 100 \\ = 15rt \\ = 15 \times 20 \\ = 300$

hope it helps!