if the interior angle of regular polygon is 108 .the polygon has ..........sides
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Good mng.
.here is your answer
let the number of side of the given polygon =n
by question
sum of angle= 108
(n-2)×180=108
180n-360=108
180n=108+360
180n=468
n=468÷180=2.6
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Hello friend
here is your answer
Each interior angle of polygon is 108°. so each interior angle of polygon is 180° - 108° = 72°, so the number of the sides are 360° / 72° = 5 . it is regular Pentagon
hope it helps
here is your answer
Each interior angle of polygon is 108°. so each interior angle of polygon is 180° - 108° = 72°, so the number of the sides are 360° / 72° = 5 . it is regular Pentagon
hope it helps
attinderpaul55225:
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