Question

If the interior angles of triangle are in ap and smallest angle is 40. find remaining angle.

Answer 1

Here is your answer

let the angles of given triangle be (a-d)°, a° and (a+d)°

so, a-d +a+ a+d = 180
3a= 180
a = 180/3
a= 60

a/q. a-d = 40. (a-d will be smallest)
60-d = 40
d= 20

so third angle is a+d= 60+20=80

hence, the three angles are 40°, 60° and 80°

hope it is useful

Answer 2

sum of the angles in a triangle equals to 180 degrees
three angles are in ap
let the angles are
a-d,a,a+d
a-d + a +a+d=180
3a=180
a=60
given smallest angle is 40 Degrees
a-d =40
a_40=d
60-40=d
so d=20
a+ d =60+20=80
so three angles are
40,60,80
I hope it will help you mark as brainliest answer!