If the internal resistance of the cell is one ohm, find the
current supplied by the cell in the circuit shown in figure.
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1/R1= 1/8 +1/8= 1/4 ohm
1/R2= 1/4+ 1/4 =1/2ohm
net resistance = 2+1= 3ohm
v=ir
i= 0.75/3= 0.25 A
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