If the ionisation energy for hydrogen atom is 13.6ev, then ionisation energy for He+ ion should be
a) 13.6ev
b) 6.8ev
C) 54.4ev
d) 72.2ev explain
Answers
Answered by
30
Heya!!
Here's your answer!!!
= number of electrons in H = 1
= number of neutron in H = 0
= ionisation energy for H atom = 13.6ev
= as number of electron in Helium = 2
= and number of neutron in Helium = 2
= ionisation energy for Helium atom
= 54.4ev
Glad help you
it helps you
thank you
@vaibhavhoax
#born with attitude
Here's your answer!!!
= number of electrons in H = 1
= number of neutron in H = 0
= ionisation energy for H atom = 13.6ev
= as number of electron in Helium = 2
= and number of neutron in Helium = 2
= ionisation energy for Helium atom
= 54.4ev
Glad help you
it helps you
thank you
@vaibhavhoax
#born with attitude
rafia86:
are u gaurav
Answered by
7
E = (13.6xZ^2) / n^2 eV
Where,
n = number of orbit = 1
Z = atomic number = 2 (for He)
E => (13.6x2^2) / 1^2
E => (13.6x4)
=> 54.4 eV
So....
Correct option: C)
Where,
n = number of orbit = 1
Z = atomic number = 2 (for He)
E => (13.6x2^2) / 1^2
E => (13.6x4)
=> 54.4 eV
So....
Correct option: C)
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