Question

If the k.E of a body about an axis is 9j and the moment of inertia is 2kg/mtr square. Then the angular velocity about the axis of rotation

Answer 1

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Answer 2

Answer:

3 rad/s

Explanation:

It is given that,

Kinetic energy of a body, KE = 9 J

Moment of inertia, I = 2 kg/m²

Here, the rotational kinetic energy is equal to the mechanical kinetic energy:

$\dfrac{1}{2}I\omega^2=\dfrac{1}{2}mv^2$

$\omega^2=\dfrac{2\times KE}{I}$

$\omega^2=\dfrac{2\times 9}{2}$

$\omega^2=9$

$\omega=3\ rad/s$

Hence, the angular velocity about the axis of rotation will be 3 radian/s.