Question

If the K.E. of
é increases by 44% find
the percentage change in its De Broglie wavelength
Vam (k. E)​

Answer 1

$\huge\star{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}⋆$

Kinetic Energy, K.E=

2

1

mv

2

Momentum, P=mv

K.E=

2m

P

2

......(1)

After increasing 44 % in kinetic energy.

(1+

100

44

)K.E=

2m

P

new

2

....(2)

P

P

new

=

1

1.44

=1.2

P

new

=1.2P=(1+

100

20

)P

P

new

−P=

100

20

P

Hence, momentum increase 20 %

Answer 2

Explanation:

Answer :-

• It will increase 20%.

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