If the ka of a monoprotic weak acid is 2.9* 10^6. What is the ph of a 0.45 m solution of this acid?
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pH= 1/2 (pka-logC)
pH=1/2 (-log2.9*10^6 - log0.1)
pH= 1/2 {6.462 - (-1)}
pH = 1/2 (7.462)
pH= 3.731
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