Question

if the kinetic energy increase to 400%then it's momentum how much increase.​

Answer 1

Answer:

Momentum of a body of given mass, is directly proportiional to its velocity. In fact momentum is mass multiplied by velocity.

Kinetic energy of a body of given mass, is directly proportiional to its square of its velocity.

When momentum is doubled, mass remaining constant, this means velcity is doubled.

Hence, kinetic energy becomes

2

2

=

4

times

i.e. say from

100

units to

400

units.

and percentage increase in kinetic energy is

400

−

100

=

300

%

.

Answer 2

Answer:

123.6 %

Explanation:

WHEN THE K.E INCREASES BY 400%, THE NEW K.E WILL BE

K' = 400%K + K

K' = 4K + K

K' = 5K → (i)

WE KNOW THAT K.E, K = $P^{2}$ / 2m                   (m IS MASS OF OBJECT)

THEREFORE EQ. (i) BECOMES

$P' ^{2}$ / 2m = 5 * $P^{2}$ / 2m                  

(2m GETS CANCELLED BOTH SIDES)

$P' ^{2}$ = 5 * $P^{2}$

THEREFORE..

P' =  $\sqrt{5}$ P → (ii)

% CHANGE IN MOMENTUM = ( P' - P / P ) * 100

= ( $\sqrt{5}$ P - P / P ) * 100         ($\sqrt{5}$ = 2.236)

= ( 1.236P / P ) * 100

= 1.236 * 100  %

= 123.6 %

THEREFORE INCREASE IN MOMENTUM IS 123.6 %

HOPE IT HELPS

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