Physics, asked by Muskangupta1772, 11 months ago

If the kinetic energy is increased by 100%% what is the percentage change in its momentum

Answers

Answered by shivendrass
0
Since, increase in KE by % means that KE is being doubled.

CASE 1: KE=mv²/2 = m²v²/2m =(mv)²/2m

KE= p²/2m {p is momentum}

p=√2(KE)m........(i)

CASE 2: 2KE= mv²/2 =(mv)²/2{doub. KE

2KE=p²/2m

p'=2√(KE)m........(ii)

Therefore, percentage change in 'p'(momentum);

%=p/p' =2{√(KE)m}× / √2(KE)m

=200 / √2

=10√2 / √2

=10% answerrrrrrrrrrrrrrrrrrr......

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