Question

If the kinetic energy is reduced by 64%, what will be the change in momentum?

Answer 1

Answer:

Let percentage decrease in momentum  =X %

Decrease in momentum   mv1−mv2=m(v1−v2)=(0.0X)mv1

we can write it like this -      v2=(1−0.0X)v1             ....(1)       

Change in KE -      1/2m(v12−v22)=0.1921mv1/2

 ⟹v22=0.81v12

By equation (1) we get  (1−0.0X)2=0.81

  ⟹X=10