Question

If the kinetic energy of a body about an axis is 9Joule and moment of inertia is 2kg-m^2 then the angular velocity of the body about the axis of rotation in radian per second is
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I am asking it 2nd time

Answer 1

I am in trouble so I'm solve another time

Answer 2

Answer:

The angular velocity of the body about the axis of rotation is 3 rad/s.

Explanation:

Given that,

Kinetic energy = 9 J

Moment of inertia $I = 2 kg-m^2$

We know that,

The kinetic energy of the body

$K.E = \dfrac{1}{2}I\omega^2$.....(I)

Put the value of I and K.E in equation (I)

$\dfrac{1}{2}\times2\times\omega^2=9$

The angular velocity of the body

$\omega^2= 9$

$\omega= 3\ rad/s$

Hence, The angular velocity of the body about the axis of rotation is 3 rad/s.