If the kinetic energy of a body increases by 125% its linear momentum increase by
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Answer:In this domain, an increase of KE of 125% is the result of its momentum increasing by the square root of 125%. At the other end of the velocity scale, KE = (γ-1)mc^2, while momentum is γmv= βγmc. If KE increases by 125%, then (γ'-1) = (γ-1)*5/4.
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