If the kinetic energy of a body increases by 125%, the percentage increase in its momentum is,
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6
Answer:
Explanation:
P²=2(K.E.)m=>P=√(2m×KE)
As KE is increased by 125% =>new one becomes (125+100)/100=2.25 times the original.
=>P² be 2.25 times the original momentum
=P becomes √(2.25)=1.5 times the original.
= the % increase
in P={(1.5–1)/1}×100=50%.Ans..
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0
Answer:
the kinetic energy of a body increases by 125%, the percentage increase in its momentum is 50%
Explanation:
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