if the kinetic energy of a body increases by 300% by what will be the linear momentum of a body increases
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The momentum increases by 100 %.
Let initial kinetic energy be K and momentum be p.
K=½mv2 (Equation 1)
If K increases by 300 %, it increases by a factor of 300%100%=3.
So the new kinetic energy is
K'=K+3K=4K
From Equation 1: v=√2Km
The initial momentum p=mv=m×√2Km=√m2×2Km=√2Km
The new momentum p'=√2K'm
So p'p=√2K'm2Km
p'p=√K'K
p'p=√4KK
p'p=2
p'=2p
% change = p'–pp×100%=2p–pp×100%=100%
% increase in momentum = 100%
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