Question

If the kinetic energy of a body increases by 300 % then the linear momentum of the body increases by

Answer 1

HEY BUDDY..!!!

HERE IS UR ANSWER...


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♠️ First we'll find the relation b/w kinetic energy and momentum .

✔️ K = 1 / 2 m ( v )^2

⏺️ Now multiplying and dividing it with mass ( m )

=> k = 1 / 2 m . ( v )^2 × m / m

=> k = ( m v )^2 / 2 m

=> k = ( P )^2 / 2 m // m v = P


✔️ K = ( P )^2 / 2 m


♠️ Now K increase 300 % K , i.e

=> K ' = K + 300 K / 100

=> K ' = K + 3 K

=> K ' = 4 K

▶️ Also K ' = ( P ' )^2 / 2 m

⏺️ Now putting value of K

=> K ' = 4 ( ( P )^2 / 2 m )

=> ( P ' )^2 / 2 m = 4 ( ( P )^2 / 2 m )

=> ( P ' )^2 = 4 ( P )^2

=> P ' = √ 4 ( P )^2

=> P ' = 2 P


♠️ Now % Change or increase in momentum

=> ( P ' - P ) / P × 100 %

=> ( 2 P - P ) / P × 100%

=> P / P × 100 %

=> 100 %


♠️ The momentum increase is 100%



HOPE HELPED..

JAI HIND..

:-)

Answer 2

Answer:

Explanation:

Please refer the below attachment.