Question

If the kinetic energy of a body is increased by300%, what will be the percentage change in momentum of body

Answer 1

Answer:

100%

Explanation:

Kinetic energy

k=1/2m(P2)

or P=√2mk

If kinetic energy of a body is increased by 300%,let it's momentum becomes P.

New kinetic energy

k=k+300/100k=4k {Initial KE =K' or Final KE=K'}

Therefore, momentum is given by

P'=√2mk=2P

Hence, percentage change (increased) in momentum is

∆P/P×100=P'-P/P×100

={P'/P-1}×100

={2P/P-1}×100

=100% Ans.