if the kinetic energy of a given body is increased by 2% then its linear momentum is increased by
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Answer:
Correct option is
B
44
We have,
K.E.=2mP2
ΔK.E. = 2mPf2 -2mPi2
=2m(56P)2-2mP2
=50m36P2−25P2
=50m11P2
Now,
% Change = KEiΔKE
=2mP250m11P2×100
=2511×100
=44%
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