Question

If the kinetic energy of an electron in bohrs orbit odd H atoms is 3.4 eV,then angular momentum of electron in that orbit is?

Answer 1

Answer:

Explanation:

We know

Energy of an electron in Bohr’s orbit is

E = -13.6 * (z^2/n^2) eV

here the value of z is 1 because the atomic number of hydrogen is 1 so we have to calculate the value of n

-0.544 = -13.6 * 1/n^2

n^2 = -13.6 / -0.544

n^2 = 25

Therefore n = 5

Now we also know that angular momentum (L) of an electron in Bohr’s orbit is

L= n*h/2*π

L = 5*6.626*10^(-34)/2*π

Therefore L = 5.27 * 10^(-34) kg m^2/s