Question

If the kinetic energy of body becomes four times of its initial value, then new momentum will

Answer 1

Let us consider a body of mass m.

Let the body is moving with velocity v.

The kinetic energy of the body   $K.E=\frac{1}{2} mv^2$

The momentum of the body [ P] = m×v

   We know   $K.E=\frac{1}{2} mv^2$

                              $=\frac{1}{2} \frac{m^2v^2}{m}$

                              $=\frac{1}{2} \frac{P^2}{m}$

                      $P^2=2m*K.E$

                      $P=\sqrt{2m*K.E}$

                      $P\ \alpha \ \sqrt{K..E}$      [ ∵m and 2 are constants]

As per the question, K.E is increased by 4 times.

Hence, from above it is obvious that momentum P will be increased by 2 times.

                             

Answer 2

Answer:

2times

Explanation:

yes

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.

.

yes it is correct