Question

. If the kinetic energy of hydrogen is 151.91 J at the pressure of
1 atmosphere, then its volume is​

Answer 1

answer : 1Litre.

it is given that, kinetic energy of hydrogen = 151.91 J at pressure of 1 atmosphere.

we have to find its volume.

according to kinetic theory of gases,

kinetic energy of hydrogen is given by, K.E = 3/2 nRT

from gas equation, PV = nRT

so, K.E = 3/2 PV

now, putting K.E = 151.91 J, P = 1atm = 1.013 × 10^5 N/m²

so, 151.91 J = 3/2 × (1.013 × 10^5 N/m²) × V

or, V = (151.91 × 2)/(3 × 1.013 × 10^5) m³

= 99.97 × 10^-5 m³ ≈ 10^-3 m³

we know, 1 m³ = 1000Litres

= 10^-3 × (1000Litres )

= 1Litres

so, volume of hydrogen is 1Litre.

[note : here it is not clear that kinetic is given of hydrogen atom or hydrogen molecules. in this situation we should use hydrogen atom. or if options are given then you should check which one is preferred. ]

Answer 2

This has been solved by one of our teacher here

https://brainly.in/question/11329379

Answer:

1Litre.

Explanation

it is given that, kinetic energy of hydrogen = 151.91 J at pressure of 1 atmosphere.

we have to find its volume.

according to kinetic theory of gases,

kinetic energy of hydrogen is given by, K.E = 3/2 nRT

from gas equation, PV = nRT

so, K.E = 3/2 PV

now, putting K.E = 151.91 J, P = 1atm = 1.013 × 10^5 N/m²

so, 151.91 J = 3/2 × (1.013 × 10^5 N/m²) × V

or, V = (151.91 × 2)/(3 × 1.013 × 10^5) m³

= 99.97 × 10^-5 m³ ≈ 10^-3 m³

we know, 1 m³ = 1000Litres

= 10^-3 × (1000Litres )

= 1Litres

so, volume of hydrogen is 1Litre.