Question

if the kinetic energy possessed by a man of 50kg is 625j the speed of man is

Answer 1

Kinetic energy = 0.5 × mass × (velocity)^2

Let speed of man be 'v'

So ,

v^2 = Kinetic energy / (0.5 × mass)

v^2 = 625/ ( 0.5×50)

v^2 = 625/ 25

v^2 = 25

v = 5 m/sec

Hence , speed of man is 5 m/sec.

Hope it helped you all the best

Answer 2

❤K.E=0.5mv^2
V=sqrt(2k.E/m)
sqrt(2*625 joules/ 50kg)
sqrt(625j/25kg)
sqrt(5m/s)
The speed of man is 5m/s