If the l.c.m. of (x - a) and (x - b) is x^2 - 2x + 1, then the value of a and b respectively are
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Given H.C.F,L.C.M of two expressions as (x+1)(x
2
+6x+8),(x+1).Let the expressions be a,b.
If a,b are two numbers and their H.C.F,L.C.M are c,d then we know that a×b=c×d.
Using this we can conclude that ;
a×b=(x+1)
2
(x
2
+6x+8)
given one of the a,b is (x
2
+3x+2)=(x+1)(x+2)
(x+1)
2
(x
2
+3x+2)=(x+1)
2
(x+2)(x+4)
=[(x+1)(x+2)(x+1)][(x+4)]
=[x
2
+3x+2][x
2
+5x+4]
hence the other expression is x
2
+5x+4
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