Math, asked by dkillu470000, 5 months ago

If the lab technician needs 30 liters of a 25% acid solution, how many liters of the 10% and the 30% acid solution should she mix to get what she needs?

Answers

Answered by pratikshapawar
1

Answer:

The answer is 7.5% of 10 liter acid and 22.5 liters of 30% is required to make 30 liters of 25% acid.

Step-by-step explanation:

Let there be x liters of 10% acid solution and y liters of 30% acid solution.

So, we can write the equation as:

x + y = 30

or

y = 30 x

x liters of 10% solution and y liters of 30% solution will add up to give 30 liters of 25% acid solution.

We can set up another equation as:

x liters of 10% acid + y liters of 30% acid = 30 liters of 25% acid

Changing percentage to decimals:

0.1(x) + 0.3(y) = 0.25(30)

By putting the values we get

0.1x + 0.3(30-x) = 7.5

0.1x + 9 -0.3x = 7.5

- 0.2x = - 1.5

x= 7.5 liters

y = 30 - x = 30 - 7.5 = 22.5 liters

Thus 7.5% of 10 liter acid and 22.5 liters of 30% is required to make 30 liters of 25% acid.

Answered by ravishankarmul
0
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