Question

If the larger of two supplementary angles exceeds the smaller by 40,then find the angles​

Answer 1

Answer:

The angles are 110° and 70°.

Step-by-step explanation:

Given :

Larger supplementary angle exceeds smaller by = 40°

To find :

The angles

Solution :

Let the -

• Smaller angle be x
• Larger angle be (x + 40)

Supplementary angles are the angles whose sum is 180°.

★ $\boxed{\sf{x + (x+40)=180}}$

$\sf{\implies} \: x + (x + 40) = 180 \\ \sf{\implies} \: 2x + 40 = 180 \\ \sf{\implies} \: 2x = 180 - 40 \\ \sf{\implies} \: 2x = 140 \\ \sf{\implies} \: x = \frac{140}{2} \\ \sf{\implies} \: x = 70$

Smaller Angle = 70°

$\rule{300}{1.5}$

★ Value of (x + 40)

$\sf{\implies} \: 70 + 40 \\ \sf{\implies} \: 110$

Larger Angel = 110°

$\therefore$ The angles are 110° and 70°.