Question

if the largest number which divides 615 and 963 leaving remainder 6 in each case.Do this in prime factorisation method dont spam it otherwise I will report yr ans​

Answer 1

Answer:

87

Step-by-step explanation:

To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e. HCF. Consider HCF be x. In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 6 from both the cases. ∴ largest number which divides 615 and 963 leaving remainder 6 in each case is 87.

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