Question

If the last term of an ap is 119 and the 8th term from the end is 91 then the common difference of the ap is

Answer 1

Step-by-step explanation:

hope this solution will help you

Answer 2

The common difference of the AP is 4.

Explanation:

As per given , we have

last term= 119

8th term from the end =91

Since the AP is starting from the end , let a = 119 and d= common difference for the given arithmetic progression from the end.

Since nth term = a+(n-1)d

It means 8th term from the end : $119+(8-1)d= 91$

$119+7d=91\\\\ 7d= 91-119\\\\ 7d= -28\\\\ d=\dfrac{-28}{7}=-4$

Now , the common difference of the AP is -d = -(-4) = 4

Hence, the common difference of the AP is 4.

# Learn more :

The 8th term of an ap is 17. Its 14th term is -29 the common difference of ap is

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