Question

If the law of conservation of mass holds good predict.how much residue would weigh if 4.2g of sodium hydrogen carbonate,10g acetic acid is added and 2.2g carbon dioxide is released.

Answer 1

as per the law of conservation of mass the sum of reactants is always equal to sum of product similarly in this case also
reactants = product
that is
(4.2+10+2.2)g = 16.4g
if something in other form releases like if any reaction takes place and a kind of gas is produced then the weight of that gas will be the part of product only

Answer 2

Answer:

Ans: NaHCO3 + CH3COOH → CH3COONa + H2O + CO2

Molecular weights

NaHCO3 = 84

CH3COOH = 60

CH3COONa = 82

CO2 = 44

84 grams NaHCO3 reacts with 60 grams of CH3COOH to form 82 grams of CH3COONa and 44 grams of CO2.

Given 6.3 grams of NaHCO3 reacts with 15 grams of CH3COOH.

Number of moles of NaHCO3 = given weight/ moleculear weight

= 6.3/84

= 0.075moles

Number of moles of CH3COOH = 15/60

= 0.25

It is to be remember that 1 mole of reactants combines to produce 1 mole of products

Thus 0.075 moles of NaHCO3 will reacts with 0.075 moles of to produce 0.075 moles of CO2.

Weight of 1 mole of CO2 is = 44 grams

Weight 0.075 moles of CO2 = (0.075*44)

= 3.3 grams

So 3.3 grams of CO2 will be produced in the reaction.

Explanation:

I hope it helps stay asking and answering questions and don't forget to follow me