Question

If the law of conservation of mass is true find the masses of sodium chloride that will react with 6.8 gram of silver nitrate to form 5.74 gram of silver Chloride and 34 gram of sodium nitrate ​

Answer 1

Answer:

We have

Explanation:

silver nitrate 6.8 gram and silver chloride that is 5.74 gram

sodium nitrate that is 34 gram

so we need to find the sodium

so according to the law of conservation of mass

. silver nitrate + sodium chloride = to Silver chloride sodium

Let sodium chloride be x

6.8 + x =5.74+34

$6.8 + x = 39.74 \\ x = 39.74 - 6.8 \\ x = 33.64$

therefore

the mass of sodium chloride in the reaction is 33.64 gram

Answer 2

Answer:

We have

Explanation:

silver nitrate 6.8 gram and silver chloride that is 5.74 gram

sodium nitrate that is 3.4 gram

so we need to find the sodium

so according to the law of conservation of mass

. silver nitrate + sodium chloride = to Silver chloride sodium

Let sodium chloride be x

6.8 + x =5.74+3.4

$6.8 + x = 9.14 \\ x = 9.14 - 6.8 \\ x = 2.34$

therefore

the mass of sodium chloride in the reaction is 2.3 4 gram